United States presidential election in the District of Columbia, 1992
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The 1992 United States presidential election in the District of Columbia took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
The District of Columbia, heavily Democratic, was won in a landslide by Governor Bill Clinton (D-Arkansas) with 84.64% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 9.10%. Businessman Ross Perot (I-Texas) finished in third, with 4.25% of the popular vote.[1] Clinton ultimately won the national vote, defeating incumbent President Bush and Perot.[2]
Results
United States presidential election in the District of Columbia, 1992[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Bill Clinton | 192,619 | 84.64% | 3 | |
Republican | George H.W. Bush (incumbent) | 20,698 | 9.10% | 0 | |
Independent | Ross Perot | 9,681 | 4.26% | 0 | |
New Alliance | Lenora Fulani | 1,459 | 0.64% | 0 | |
Independent | Ronald Daniels | 1,446 | 0.64% | 0 | |
Libertarian | Andre Marrou | 467 | 0.21% | 0 | |
N/A | Write-ins | 1,202 | 0.53% | 0 | |
Totals | 227,572 | 100.00% | 3 |
References
- 1 2 "1992 Presidential General Election Results - District of Columbia". U.S. Election Atlas. Retrieved 8 June 2012.
- ↑ "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 8 June 2012.
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