United States presidential election in New Jersey, 1872
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Elections in New Jersey | ||||||||||
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The 1872 United States presidential election in New Jersey took place on November 5, 1872. All contemporary 37 states were part of the 1872 United States presidential election. The state voters chose nine electors to the Electoral College, which selected the president and vice president.
New Jersey was won by the Republican nominees, incumbent President Ulysses S. Grant of Illinois and his running mate Senator Henry Wilson of Massachusetts. Grant and Wilson defeated the Liberal Republican and Democratic nominees, former Congressman Horace Greeley of New York and his running mate former Senator and Governor Benjamin Gratz Brown of Missouri by a margin of 9.04%.
Results
United States presidential election in New Jersey, 1872[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Ulysses S. Grant of Illinois | Henry Wilson of Indiana | 91,656 | 54.52% | 9 | 100.00% | ||
Liberal Republican | Horace Greeley of New York | Benjamin Gratz Brown of Missouri | 76,456 | 45.48% | 0 | 0.00% | ||
Total | 168,112 | 100.00% | 9 | 100.00% |
References
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