Oak Hill (Herkimer County, New York)
Oak Hill | |
---|---|
Oak Hill Location of Oak Hill within New York | |
Highest point | |
Elevation | 984 feet (300 m) |
Coordinates | 43°03′03″N 75°02′15″W / 43.05083°N 75.03750°WCoordinates: 43°03′03″N 75°02′15″W / 43.05083°N 75.03750°W [1] |
Geography | |
Location | NW of Herkimer, New York, U.S. |
Topo map | USGS Ilion |
Oak Hill is a summit located in Central New York Region of New York located in the Town of Herkimer in Herkimer County, northwest of Herkimer.
References
- ↑ "Oak Hill". Geographic Names Information System. United States Geological Survey. Retrieved 2017-12-08.
This article is issued from
Wikipedia.
The text is licensed under Creative Commons - Attribution - Sharealike.
Additional terms may apply for the media files.