1948 United States presidential election in Delaware

The 1948 United States presidential election in Delaware took place on November 2, 1948, as part of the 1948 United States presidential election. Delaware voters chose 3[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

United States presidential election in Delaware, 1948

November 2, 1948[1]

All 3 Delaware votes to the Electoral College
 
Nominee Thomas E. Dewey Harry S. Truman
Party Republican Democratic
Home state New York Missouri
Running mate Earl Warren Alben W. Barkley
Electoral vote 3 0
Popular vote 69,588 67,813
Percentage 50.0% 48.8%

County Results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

Delaware was won by Governor Thomas Dewey (RNew York), running with Governor Earl Warren, with 50.04% of the popular vote, against incumbent President Harry S. Truman (DMissouri), running with Senator Alben W. Barkley, with 48.76% of the popular vote.[3][4] This is the last time that New Castle county did not back the statewide winner.

Results

United States presidential election in Delaware, 1948
Party Candidate Votes %
Republican Thomas Dewey 69,588 50.04%
Democratic Harry S. Truman (inc.) 67,813 48.76%
Progressive Henry A. Wallace 1,050 0.75%
Write-in 622 0.45%
Total votes 139,073 100.00%

References


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