1852 United States presidential election in Delaware
The 1852 United States presidential election in Delaware took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Delaware | ||||||||||||
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Delaware voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Delaware by a margin of 0.19%.
Results
United States presidential election in Delaware, 1852[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Franklin Pierce of New Hampshire | William R. King of Alabama | 6,318 | 49.85% | 3 | 100.00% | ||
Whig | Winfield Scott of New Jersey | William Alexander Graham of North Carolina | 6,293 | 49.66% | 0 | 0.00% | ||
Free Soil | John P. Hale of New Hampshire | George Washington Julian of Indiana | 62 | 0.49% | 0 | 0.00% | ||
Total | 12,673 | 100.00% | 3 | 100.00% |
References
- "1852 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 17 March 2015.
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