1928 United States presidential election in Oklahoma

The 1928 United States presidential election in Oklahoma took place on November 6, 1928, as part of the 1928 United States presidential election which was held throughout all contemporary 48 states. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1928 United States presidential election
1928 United States presidential election in Oklahoma
November 6, 1928
 
Nominee Herbert Hoover Al Smith
Party Republican Democratic
Home state California New York
Running mate Charles Curtis Joseph T. Robinson
Electoral vote 10 0
Popular vote 394,046 219,174
Percentage 63.82% 35.44%
President before election

Calvin Coolidge
Republican

 Elected President

Herbert Hoover
Republican

Elections in Oklahoma
Government

Oklahoma voted for the Republican nominee, Secretary of Commerce Herbert Hoover of California, over the Democratic nominee, Governor Alfred E. Smith of New York. Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith ran with Senator Joseph Taylor Robinson of Arkansas.

Hoover won the state by a margin of 28.28 percentage points.

Results
1928 United States presidential election in Oklahoma[1]
Party Candidate Votes Percentage Electoral votes
Republican Herbert Hoover 394,046 63.72% 10
Democratic Alfred E. Smith 219,174 35.44% 0
Socialist Norman Thomas 3,924 0.63% 0
Farmer Labor Frank Webb 1,283 0.21% 0
Totals 618, 427 100.00% 10

References
  1. "1928 Presidential General Election Results - Oklahoma". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved 2013-08-02.
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