1928 United States presidential election in Nebraska

The 1928 United States presidential election in Nebraska was held on November 6, 1928. Nebraska voters chose eighteen electors to the Electoral College, who voted for president and vice president.

1928 United States presidential election in Nebraska
November 6, 1928
 
Nominee Herbert Hoover Al Smith
Party Republican Democratic
Home state California New York
Running mate Charles Curtis Joseph T. Robinson
Electoral vote 8 0
Popular vote 345,745 197,959
Percentage 63.19% 36.18%
President before election

Calvin Coolidge
Republican

 Elected President

Herbert Hoover
Republican

The Republican candidate Herbert Hoover won the state by 147,786 votes or close to 27.01 percentage points against Al Smith.[1]

Results
1928 United States presidential election in Nebraska
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Herbert Hoover of California Charles Curtis of Kansas 345,745 63.19% 8 100%
Democratic Al Smith of New York Joseph Taylor Robinson of Arkansas 197,959 36.18% 0 0.00%
Socialist Norman Thomas of New York James Hudson Maurer of Pennsylvania 3,434 0.63% 0 0.00%
Various Write-ins Various 6 0.00% 0 0
Total 547,144 100% 8 100%

References
  1. "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved 2020-03-04.
Elections in Nebraska
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