1920 United States presidential election in Oklahoma

The 1920 United States presidential election in Oklahoma took place on November 2, 1920, as part of the 1920 United States presidential election which was held throughout all contemporary 48 states. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.

1920 United States presidential election in Oklahoma

November 2, 1920

Nominee Warren G. Harding James M. Cox Eugene V. Debs Party Republican Democratic Socialist Home state Ohio Ohio Indiana Running mate Calvin Coolidge Franklin D. Roosevelt Seymour Stedman Electoral vote 10 0 0 Popular vote 243,831 217,053 25,726 Percentage 50.11% 44.61% 5.29%

President before election Woodrow Wilson Democratic Elected President Warren G. Harding Republican

Elections in Oklahoma
Federal government Presidential Elections 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 2020 Presidential primaries Democratic 2004 2008 2012 2016 2020 Republican 2004 2008 2012 2020 Senate elections 1968 1974 1978 1980 1984 1986 1990 1992 1994 (special) 1996 1998 2002 2004 2008 2010 2014 2014 (special) 2016 2020 House of Representatives elections 2000 2002 2004 2006 2008 2010 2012 2014 2016 2018 2020 Special elections Senate, 1994 1st district, 2002 Senate, 2014
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Ballot measures 2004 Question 711
Oklahoma City government Mayoral elections 2014 2018
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Government

Oklahoma voted for the Republican nominee, Ohio Senator Warren G. Harding, over the Democratic nominee, Ohio Governor James M. Cox and Socialist nominee Eugene V. Debs of Indiana.

Harding ran with Massachusetts Governor Calvin Coolidge, while Cox ran with Assistant Secretary of the Navy Franklin D. Roosevelt of New York and Debs ran with Seymour Stedman of Illinois.

Harding won the state by a margin of 5.5 percentage points. As a result of his win, Harding became the first Republican presidential candidate to win Oklahoma.