1852 United States presidential election in Alabama

The 1852 United States presidential election in Alabama took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

United States presidential election in Alabama, 1852

November 2, 1852
 
Nominee Franklin Pierce Winfield Scott
Party Democratic Whig
Home state New Hampshire New Jersey
Running mate William R. King William A. Graham
Electoral vote 9 0
Popular vote 26,881 15,061
Percentage 60.89% 34.12%

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

Alabama voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Alabama by a margin of 26.77%.

Results

United States presidential election in Alabama, 1852[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 26,881 60.89% 9 100.00%
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 15,061 34.12% 0 0.00%
Southern Rights George M. Troup N/A 2,205 4.99% 0 0.00%
Total 44,147 100.00% 9 100.00%

References

  1. "1852 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved 2 December 2017.
  2. "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.


This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.