1840 United States presidential election in Arkansas

The 1840 United States presidential election in Arkansas took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

United States presidential election in Arkansas, 1840

October 30 – December 2, 1840
 
Nominee Martin Van Buren William H. Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard M. Johnson John Tyler
Electoral vote 3 0
Popular vote 6,679 5,160
Percentage 56.42% 43.58%

President before election

Martin Van Buren
Democratic

Elected President

William H. Harrison
Whig

Arkansas voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Arkansas by a margin of 12.84%.

Results

United States presidential election in Arkansas, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 6,679 56.42% 3 100.00%
Whig William Henry Harrison of Ohio John Tyler of Virginia 5,160 43.58% 0 0.00%
Total 11,839 100.00% 3 100.00%

References

  1. "1840 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved 23 December 2013.


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