1840 United States presidential election in Mississippi

The 1840 United States presidential election in Mississippi took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

United States presidential election in Mississippi, 1840

October 30 - December 2, 1840
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 4 0
Popular vote 19,515 17,010
Percentage 53.43% 46.57%

County Results


Harrison:      50-60%      60-70%      70-80%      80-90%
Tie:      50%
Van Buren:      50-60%      60-70%      70-80%

     80-90%

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

Mississippi voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Mississippi by a margin of 6.86%. As of 2016, this is the only election in American history in which Mississippi and Alabama voted for different candidates.

Results

United States presidential election in Mississippi, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 19,515 53.43% 4 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 17,010 46.57% 0 0.00%
Total 36,525 100.00% 4 100.00%

References

  1. "1840 Presidential General Election Results - Mississippi". U.S. Election Atlas. Retrieved 23 December 2013.


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