United States presidential election in Ohio, 1832
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The 1832 United States presidential election in Ohio took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 21 representatives, or electors to the Electoral College, who voted for President and Vice President.
Ohio voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay, and the Anti-Masonic Party candidate, William Wirt. Jackson won Ohio by a margin of 2.98%.
Results
United States presidential election in Ohio, 1832[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 81,246 | 51.33% | 21 | |
National Republican | Henry Clay | 76,539 | 48.35% | 0 | |
Anti-Masonic | William Wirt | 509 | 0.32% | 0 | |
Totals | 158,294 | 100.0% | 21 | ||
References
- ↑ "1832 Presidential General Election Results - Ohio". U.S. Election Atlas. Retrieved 12 April 2013.
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