United States presidential election in New Hampshire, 1788–89

United States presidential election in New Hampshire, 1789

December 15, 1788 – January 10, 1789

Nominee George Washington John Adams Party Nonpartisan Federalist Home state Virginia Massachusetts Electoral vote 5 5 Popular vote 5,909 – Percentage 100% –

Elections in New Hampshire
Federal government Presidential elections 1788-89 1792 1796 1800 1804 1808 1812 1816 1820 1824 1828 1832 1836 1840 1844 1848 1852 1856 1860 1864 1868 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential primaries Democratic 1992 2000 2004 2008 2012 2016 Republican 2000 2004 2008 2012 2016 Local Dixville Notch Hart's Location United States Senate elections 1974 1980 1986 1990 1992 1996 1998 2002 2004 2008 2010 2014 2016 United States House elections 1992 1994 1996 1998 2000 2002 2004 2006 2008 2010 2012 2014 2016 2018
State government Gubernatorial elections 1990 1992 1994 1996 1998 2000 2002 2004 2006 2008 2010 2012 2014 2016 2018 General Court elections 2004 2006
City of Manchester Municipal elections 2009

The 1789 United States presidential election in New Hampshire took place between December 15, 1788 and January 10, 1789, as part of the 1788–1789 United States presidential election to elect the first President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire unanimously voted for nonpartisan candidate and commander-in-chief of the Continental Army, George Washington. The total vote is composed of 5,909 for Federalist electors, all of whom were supportive of Washington.^[1]

Results

References