United States presidential election in Maine, 1860

United States presidential election in Maine, 1860
November 2, 1860

 
Nominee Abraham Lincoln Stephen A. Douglas John C. Breckinridge
Party Republican Democratic Southern Democratic
Home state Illinois Illinois Kentucky
Running mate Hannibal Hamlin Herschel Vespasian Johnson Joseph Lane
Electoral vote 8 0 0
Popular vote 62,811 29,693 6,368
Percentage 62.24% 29.42% 6.31%
President before election

James Buchanan
Democratic

 Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in Maine took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose eight electors of the Electoral College, who voted for president and vice president.

Maine was won by Republican candidate Abraham Lincoln, who won by a margin of 32.82%.

With 62.24% of the popular vote, Maine would prove to be Lincoln's fourth strongest state in terms of popular vote percentage after Vermont, Minnesota and Massachusetts[1].

Results

United States presidential election in Maine, 1860[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Abraham Lincoln of Illinois Hannibal Hamlin of Maine 62,811 62.24% 8 100.00%
Democratic Stephen A. Douglas of Illinois Herschel Vespasian Johnson of Georgia 29,693 29.42% 0 0.00%
Southern Democratic John C. Breckinridge of Kentucky Joseph Lane of Oregon 6,368 6.31% 0 0.00%
Constitutional Union John Bell of Tennessee Edward Everett of Massachusetts 2,046 2.03% 0 0.00%
Total 100,918 100.00% 8 100.00%

References

  1. ↑ "1860 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ↑ "1860 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved 17 March 2015.
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