Dutch general election, 1917

Kingdom of the Netherlands
Azure, billetty Or a lion with a coronet Or armed and langued Gules holding in his dexter paw a sword Argent hilted Or and in the sinister paw seven arrows Argent pointed and bound together Or. [The seven arrows stand for the seven provinces of the Union of Utrecht.] The shield is crowned with the (Dutch) royal crown and supported by two lions Or armed and langued gules. They stand on a scroll Azure with the text (Or) "Je Maintiendrai" (French for "I will maintain".)
This article is part of a series on the
politics and government of
the Netherlands

General elections were held in the Netherlands on 5 and 15 June 1917 to elect members of the House of Representatives of the Dutch Parliament. The elections were held following an agreement between the seven political parties with seats in parliament to allow a change in the constitution to introduce universal male suffrage and proportional representation. Polling was held for 50 constituencies with only one candidate on 5 June, in which 50 MPs were elected. In the other 50 constituencies with opposition candidates, voting was held on 15 July. A second round was required in Amsterdam, where Social Democratic Workers' Party candidate Adriaan Gerhard was re-elected.

1,078,205 citizens were eligible to vote of which 230,310 cast a vote, representing a turnout of 21.36%.[1]

Results

Party Votes % Seats +/–
General League of Roman Catholic Caucuses24–1
Liberal Union21+1
Social Democratic Workers' Party15–2
Anti-Revolutionary Party12+1
League of Free Liberals100
Christian Historical Union9–1
Free-thinking Democratic League8+1
Other parties1–
Total230,3101001000
Registered voters/turnout1,078,20521.36––

References

  1. ↑ "Tweede Kamer 15 juni 1917". Kiesraad (in Dutch).
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.