Wildwood, Kentucky

Wildwood is located in eastern Jefferson County at 38°15′02″N 85°34′27″W.[3] It is bordered to the west by Lyndon and otherwise by consolidated Louisville/Jefferson County. U.S. Route 60 (Shelbyville Road) forms the southern boundary of the community, and downtown Louisville is 10 miles (16 km) to the west.

According to the United States Census Bureau, Wildwood has a total area of 0.07 square miles (0.19 km²), all land.[2]

At the 2000 census there were 247 people, 111 households, and 75 families living in the city. The population density was 2,935.8 people per square mile (1,192.1/km²). There were 115 housing units at an average density of 1,366.8 per square mile (555.0/km²). The racial makeup of the city was 98.79% White, 0.40% Native American, 0.40% Asian, and 0.40% from two or more races. Hispanic or Latino of any race were 1.21%.[5]

Of the 111 households 25.2% had children under the age of 18 living with them, 58.6% were married couples living together, 8.1% had a female householder with no husband present, and 32.4% were non-families. 28.8% of households were one person and 15.3% were one person aged 65 or older. The average household size was 2.23 and the average family size was 2.72.

The age distribution was 18.6% under the age of 18, 4.5% from 18 to 24, 18.6% from 25 to 44, 28.7% from 45 to 64, and 29.6% 65 or older. The median age was 49 years. For every 100 females, there were 80.3 males. For every 100 females age 18 and over, there were 73.3 males.

The median household income was $61,250 and the median family income was $75,484. Males had a median income of $52,083 versus $37,143 for females. The per capita income for the city was $38,251. None of the families and 0.8% of the population were living below the poverty line, including no under eighteens and 2.7% of those over 64.