Boles Acres, New Mexico

Boles Acres is located at 32°49′6″N 105°58′29″W (32.818336, -105.974675).[2]

According to the United States Census Bureau, the CDP has a total area of 12.2 square miles (32 km²), all of it land.[1]

As of the census[3] of 2000, there were 1,172 people, 463 households, and 355 families residing in the CDP. The population density was 90.8 people per square mile (35.1/km²). There were 562 housing units at an average density of 43.6 per square mile (16.8/km²). The racial makeup of the CDP was 86.86% White, 1.28% African American, 0.34% Native American, 1.11% Asian, 0.17% Pacific Islander, 6.91% from other races, and 3.33% from two or more races. Hispanic or Latino of any race were 15.44% of the population.

There were 463 households, out of which 30.5% had children under the age of 18 living with them, 66.1% were married couples living together, 6.5% had a female householder with no husband present, and 23.3% were non-families. 20.5% of all households were made up of individuals, and 6.5% had someone living alone who was 65 years of age or older. The average household size was 2.53 and the average family size was 2.91.

In the CDP, the population was spread out, with 24.4% under the age of 18, 6.4% from 18 to 24, 25.8% from 25 to 44, 28.6% from 45 to 64, and 14.8% who were 65 years of age or older. The median age was 41 years. For every 100 females, there were 99.3 males. For every 100 females age 18 and over, there were 101.8 males.

The median income for a household in the CDP was $39,048, and the median income for a family was $51,029. Males had a median income of $32,656 versus $19,779 for females. The per capita income for the CDP was $18,207. About 9.4% of families and 13.3% of the population were below the poverty line, including 20.0% of those under age 18 and 13.5% of those age 65 or over.