1998 United States House of Representatives elections in Kansas
The 1998 United States House of Representatives elections in Kansas were held on November 3, 1998 to determine who will represent the state of Kansas in the United States House of Representatives. Kansas has four seats in the House, apportioned according to the 1990 United States Census. Representatives are elected for two-year terms.
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Ballot measures
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Overview
| United States House of Representatives elections in Kansas, 1998[1] | |||||
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| Party | Votes | Percentage | Seats | +/– | |
| Republican | 450,025 | 61.86% | 3 | -1 | |
| Democratic | 272,252 | 37.43% | 1 | +1 | |
| U.S. Taxpayers | 5,171 | 0.71% | 0 | - | |
| Totals | 727,448 | 100.00% | 4 | - | |
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Jerry Moran | 152,775 | 80.67 | |
| Democratic | Jim Phillips | 36,618 | 19.33 | |
| Total votes | 189,393 | 100.00 | ||
| Republican hold | ||||
References
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