Waukeenah, Florida

Waukeenah, Florida
Census-designated place
Waukeenah
Waukeenah
Coordinates: 30°24′41″N 83°57′12″W / 30.41139°N 83.95333°W / 30.41139; -83.95333Coordinates: 30°24′41″N 83°57′12″W / 30.41139°N 83.95333°W / 30.41139; -83.95333
Country  United States
State  Florida
County  Jefferson
Area[1]
 • Total 3.22 sq mi (8.35 km2)
 • Land 3.16 sq mi (8.18 km2)
 • Water 0.07 sq mi (0.17 km2)
Elevation 195 ft (59 m)
Population (2010)
 • Total 272
 • Density 86.1/sq mi (33.25/km2)
Time zone UTC-5 (Eastern (EST))
 • Summer (DST) UTC-4 (EDT)
Area code(s) 850
FIPS code 12-75425[1]
GNIS feature ID 0294191[2]

Waukeenah is an unincorporated community and census-designated place (CDP) in Jefferson County, Florida, United States. As of the 2010 census the population was 272.[1]

Geography

Waukeenah is located at 30°24′40″N 83°57′11″W / 30.4111°N 83.9531°W / 30.4111; -83.9531 (30.4111, -83.9531),[3] near the intersection of US 27/State Road 20 and County Road 259. It is 11 miles (18 km) southwest of Monticello, the Jefferson county seat, and 20 miles (32 km) east of Tallahassee, the state capital.

Waukeenah was once a resting point for travelers using the Old St. Augustine road, which started in St. Augustine and went to Pensacola, Florida.

According to the U.S. Census Bureau, the Waukeenah CDP has a total area of 3.2 square miles (8.4 km2), of which 3.2 square miles (8.2 km2) are land and 0.1 square miles (0.2 km2), or 2.04%, are water.[1]

References

  1. 1 2 3 4 "Geographic Identifiers: 2010 Census Summary File 1 (G001): Waukeenah CDP, Florida". American Factfinder. U.S. Census Bureau. Retrieved May 1, 2018.
  2. ↑ U.S. Geological Survey Geographic Names Information System: Waukeenah, Florida
  3. ↑ "US Gazetteer files: 2010, 2000, and 1990". United States Census Bureau. 2011-02-12. Retrieved 2011-04-23.


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