United States presidential election in Nevada, 1884


United States presidential election in Nevada, 1884

November 4, 1884
Turnout 20.52% of the total population Decrease 8.94 pp[1]

 
Nominee James G. Blaine Grover Cleveland
Party Republican Democratic
Home state Ohio New York
Running mate John A. Logan Thomas A. Hendricks
Electoral vote 3 0
Popular vote 7,193 5,578
Percentage 56.21% 47.60%

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Nevada took place on November 4, 1884, as part of the 1884 United States presidential election. Nevada voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president[2].

Nevada was won by Secretary of State James G. Blaine (R-Ohio), running with Senator John A. Logan, with 56.21% of the vote, against Grover Cleveland, the 28th governor of New York, (DNew York), running with the former governor of Indiana Thomas A. Hendricks, with 43.59% of the popular vote.[2]

The Greenback and Anti-Monopoly Parties both chose major general and former governor of Massachusetts Benjamin Butler and Absolom M. West, an unseated Mississippi representative, received 0.20% of the vote for the scant 26 votes they received.

Results

United States presidential election in Nevada, 1884[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican James G. Blaine of Ohio John A. Logan of Illinois 7,193 56.21% 3 100.00%
Democratic Grover Cleveland of New York Thomas A. Hendricks of Indiana 5,578 43.59 0 0.00%
Total 12,797 100.00% 3 100.00%

References

  1. "1884 Presidential Election Results Nevada Total Population Turnout".
  2. 1 2 3 "1884 Presidential Election Results Nevada".
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.