United States presidential election in Georgia, 1852

United States presidential election in Georgia, 1852
November 2, 1852

 
Nominee Franklin Pierce Winfield Scott Daniel Webster
Party Democratic Whig Whig
Home state New Hampshire New Jersey Massachusetts
Running mate William R. King William A. Graham none
Electoral vote 10 0 0
Popular vote 40,516 16,660 5,324
Percentage 64.70% 26.60% 8.50%
President before election

Millard Fillmore
Whig

 Elected President

Franklin Pierce
Democratic

The 1852 United States presidential election in Georgia took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for President and Vice President.

Georgia voted for the Democratic candidate, Franklin Pierce, over Whig candidates Winfield Scott and Daniel Webster. Daniel Webster was not chosen as the Whig Party candidate, but was placed on the ballot without permission by a group of former Whigs, now Know Nothings.[1] Pierce won Georgia by a margin of 38.10%.

Results

United States presidential election in Georgia, 1852[2][3]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 40,516 64.70% 10 100.00%
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 16,660 26.60% 0 0.00%
Whig Daniel Webster of Massachusetts N/A of N/A 5,324 8.50% 0 0.00%
Southern Rights George M. Troup N/A 126 0.20% 0 0.00%
Total 62,626 100.00% 10 100.00%

References

  1. ↑ Ogg, Frederic Austin (1914). Daniel Webster. p. 407.
  2. ↑ "1852 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 2 December 2017.
  3. ↑ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.
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