Benton Township, Elkhart County, Indiana

Benton Township
Township

Location of Benton Township in Elkhart County
Coordinates: 41°28′55″N 85°42′27″W / 41.48194°N 85.70750°W / 41.48194; -85.70750Coordinates: 41°28′55″N 85°42′27″W / 41.48194°N 85.70750°W / 41.48194; -85.70750
Country United States
State Indiana
County Elkhart
Government
 • Type Indiana township
Area
 • Total 35.9 sq mi (93 km2)
 • Land 35.84 sq mi (92.8 km2)
 • Water 0.06 sq mi (0.2 km2)
Elevation[1] 853 ft (260 m)
Population (2010)
 • Total 2,963
 • Density 82.7/sq mi (31.9/km2)
FIPS code 18-04798[2]
GNIS feature ID 453105

Benton Township is one of sixteen townships in Elkhart County, Indiana. As of the 2010 census, its population was 2,963.[3]

Geography

According to the 2010 census, the township has a total area of 35.9 square miles (93 km2), of which 35.84 square miles (92.8 km2) (or 99.83%) is land and 0.06 square miles (0.16 km2) (or 0.17%) is water.[3]

Cities and towns

Unincorporated towns

Adjacent townships

Major highways

Cemeteries

The township contains two cemeteries: Brown and Hire.

References

  • "Benton Township, Elkhart County, Indiana". Geographic Names Information System. United States Geological Survey. Retrieved 2009-09-24.
  • United States Census Bureau cartographic boundary files
  1. ↑ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. ↑ "American FactFinder". United States Census Bureau. Archived from the original on 2013-09-11. Retrieved 2008-01-31.
  3. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10.


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