Liberty, Vernon County, Wisconsin

According to the United States Census Bureau, the town has a total area of 23.1 square miles (59.7 km²), of which, 23.0 square miles (59.7 km²) of it is land and 0.04% is water.

At the 2000 census there were 167 people in 73 households, including 52 families, in the town. The population density was 7.2 people per square mile (2.8/km²). There were 123 housing units at an average density of 5.3 per square mile (2.1/km²). The racial makeup of the town was 100.00% White. Hispanic or Latino of any race were 0.60%.[2]

Of the 73 households 27.4% had children under the age of 18 living with them, 61.6% were married couples living together, 6.8% had a female householder with no husband present, and 27.4% were non-families. 23.3% of households were one person and 12.3% were one person aged 65 or older. The average household size was 2.29 and the average family size was 2.68.

The age distribution was 21.0% under the age of 18, 3.0% from 18 to 24, 27.5% from 25 to 44, 32.3% from 45 to 64, and 16.2% 65 or older. The median age was 44 years. For every 100 females, there were 98.8 males. For every 100 females age 18 and over, there were 103.1 males.

The median household income was $24,688 and the median family income was $27,500. Males had a median income of $21,250 versus $22,500 for females. The per capita income for the town was $13,986. About 11.1% of families and 14.1% of the population were below the poverty line, including none of those under the age of eighteen and 26.7% of those sixty five or over.