2019 Hungarian Open – Doubles
Dominic Inglot and Franko Škugor were the defending champions,[1] but Škugor chose to compete in Barcelona instead. Inglot played alongside Rohan Bopanna, but lost in the quarterfinals to Andre Begemann and Ernests Gulbis.
| Doubles | |
|---|---|
| 2019 Hungarian Open | |
| Champions |  |
| Runners-up |   |
| Final score | 6–3, 6–4 |
| Draw | 16 (2WC) |
| Seeds | 4 |
Ken and Neal Skupski won the title, defeating Marcus Daniell and Wesley Koolhof in the final, 6–3, 6–4.
Seeds
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
| First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 | | 6 | 7 | ||||||||||||||||||||||||
| Alt |  .svg.png){kind=small} | 3 | 5 | 1 | | 3 | 4 | ||||||||||||||||||||
| Alt |   | 6 | 7 | Alt | | 6 | 6 | ||||||||||||||||||||
  | 4 | 5 | Alt | | 2 | 77 | [6] | ||||||||||||||||||||
| 3 | | 6 | 77 | 3 | | 6 | 62 | [10] | |||||||||||||||||||
| WC |   | 0 | 64 | 3 | | 78 | 5 | [10] | |||||||||||||||||||
  | 3 | 6 | [9] |  | 66 | 7 | [7] | ||||||||||||||||||||
| 6 | 4 | [11] | 3 | | 6 | 6 | ||||||||||||||||||||
| 6 | 6 | | 3 | 4 | ||||||||||||||||||||||
  | 2 | 3 | | 6 | 77 | ||||||||||||||||||||||
| WC | | 6 | 3 | [8] | 4 | | 4 | 65 | |||||||||||||||||||
| 4 | | 2 | 6 | [10] | | 3 | 6 | [10] | |||||||||||||||||||
  | 3 | 3 | | 6 | 2 | [8] | |||||||||||||||||||||
| 6 | 6 | | 3 | 6 | [10] | |||||||||||||||||||||
| 3 | 6 | [10] | | 6 | 4 | [6] | ||||||||||||||||||||
| 2 | | 6 | 3 | [8] | |||||||||||||||||||||||
References
- "Inglot/Skugor Earn Maiden Team Title In Budapest". ATP Tour. 29 April 2018. Retrieved 20 April 2019.
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