2019 Hank Steinbrecher Cup

The 2019 Hank Steinbrecher Cup was the seventh edition of the United States Adult Soccer Association's (USASA) tournament whose winner is recognized with the title of U.S. National Amateur Champions.

2019 Hank Steinbrecher Cup
CountryUnited States of America
DatesMay 31 – June 1, 2019
Teams4
Defending championsMichigan Bucks
ChampionsFlint City Bucks (third title)
Matches played4
Goals scored17 (4.25 per match)
2018
2020

USL League Two (USL L2) side Flint City Bucks are the defending champion.

Host selection

Milwaukee Bavarian SC was selected to host the tournament.[1]

Teams

The tournament featured the 2018 USASA National Amateur Cup winner Milwaukee Bavarian SC and the defending Steinbrecher Cup winner Flint City Bucks, rebranded from Michigan Bucks. Ordinarily the tournament would have featured the 2018 PDL champion Calgary Foothills FC and the 2018 National Professional Soccer League (NPSL) champion Miami FC 2, but Calgary was ineligible due to being based in Canada and Miami was ineligible due to being a professional club. In their place, PDL runner-up Reading United AC and NPSL runner-up FC Motown were invited.[1] Chicago FC United 2018 PDL National Semi-Finalist took the USL League 2 spot after Reading elected not to participate.[2]

Matches

Bracket

The semifinal draw was held on March 1.[3]

  Semifinals     Final
                 
  USL2 Chicago FC United 3  
  NAC Milwaukee Bavarian SC 2    
      USL2 Chicago FC United 0
      Def. Flint City Bucks 3
  NPSL FC Motown 1    
  Def. Flint City Bucks 4   Third Place
 
NPSL FC Motown 3
  NAC Milwaukee Bavarian SC 1 [4]

* = after extra time

Semifinals

May 31, 2019 FC Motown1-4Flint City BucksGlendale, Wisconsin
 77' Report Timmer  42'  90'
Barone  62'
McNitt  77'
Stadium: Bavarian Sports Complex

Third-Place Match

Final

June 1, 2019 Flint City Bucks3-0Chicago FC UnitedGlendale, Wisconsin
Barone  16'
McNitt
Mwambia  38'o.g.
Report Stadium: Bavarian Sports Complex

See also

References

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