1998 Budapest Lotto Open – Doubles

Amanda Coetzer and Alexandra Fusai were the defending champions but did not compete that year.

Doubles
1998 Budapest Lotto Open
Champions Virginia Ruano Pascual
Paola Suárez
Runners-up Cătălina Cristea
Laura Montalvo
Final score4–6, 6–1, 6–1

Virginia Ruano Pascual and Paola Suárez won in the final 4–6, 6–1, 6–1 against Cătălina Cristea and Laura Montalvo.

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1. Virginia Ruano Pascual / Paola Suárez (Champions)
  2. Cătălina Cristea / Laura Montalvo (Final)
  3. Svetlana Krivencheva / Eva Melicharová (Quarterfinals)
  4. Laura Golarsa / Liezel Horn (Semifinals)

Draw

Key
First Round Quarterfinals Semifinals Final
1 V Ruano Pascual
P Suárez 		6 6  
  E Bes
K Marosi 		0 1   1 V Ruano Pascual
P Suárez 		6 6  
  S Naćuk
P Wartusch 		6 1 6   S Naćuk
P Wartusch 		1 0  
  J Halard-Decugis
J Husárová 		3 6 4 1 V Ruano Pascual
P Suárez 		6 6  
4 L Golarsa
L Horn 		6 4 6 4 L Golarsa
L Horn 		3 3  
  P Gáspár
A-G Sidot 		4 6 3 4 L Golarsa
L Horn 		6 6  
WC Z Gubacsi
R Kuti-Kis 		6 6   WC Z Gubacsi
R Kuti-Kis 		4 2  
Q E Doman
A Piski 		4 3   1 Virginia Ruano Pascual
Paola Suárez 		4 6 6
  A Dechaume-Balleret
B Rittner 		      2 Cătălina Cristea
Laura Montalvo 		6 1 1
  N Dechy
L Ghirardi 		w/o       N Dechy
L Ghirardi 		6 6  
  E Kulikovskaya
K Studeníková 		2 1   3 S Krivencheva
E Melicharová 		4 2  
3 S Krivencheva
E Melicharová 		6 6     N Dechy
L Ghirardi 		2 6 1
  S Cecchini
W Probst 		4 1   2 C Cristea
L Montalvo 		6 2 6
  S Farina
S Testud 		6 6     S Farina
S Testud 		3 3  
  V Csurgó
T Križan 		3 5   2 C Cristea
L Montalvo 		6 6  
2 C Cristea
L Montalvo 		6 7  
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