1904 United States presidential election in South Dakota
The 1904 United States presidential election in South Dakota took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. Voters chose four electors to the Electoral College, which selected the president and vice president.
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Elections in South Dakota | ||||||||||
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South Dakota was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana. The ticket won the state by a margin of 49,42%.
With 71.09% of the popular vote, South Dakota would be Roosevelt's fourth strongest victory in terms of percentage in the popular vote after Vermont, North Dakota and Minnesota.[1]
Results
1904 United States presidential election in South Dakota[2] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | Theodore Roosevelt | 72,083 | 71.09% | 4 | |
Democratic | Alton B. Parker | 21,969 | 21.67% | 0 | |
Social Democratic | Eugene Debs | 3,138 | 3.09% | 0 | |
Prohibition | Silas C. Swallow | 2,965 | 2.92% | 0 | |
Populist | Thomas E. Watson | 1,240 | 1.22% | 0 | |
Totals | 101,395 | 100.00% | 4 | ||
Voter turnout | — |
References
- "1904 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – South Dakota
Notes
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