1884 United States presidential election in Maine

The 1884 United States presidential election in Maine took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

1884 United States presidential election in Maine

November 4, 1884
 
Nominee James G. Blaine Grover Cleveland
Party Republican Democratic
Home state Maine New York
Running mate John A. Logan Thomas A. Hendricks
Electoral vote 4 0
Popular vote 72,217 52,153
Percentage 55.34% 39.97%

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

Maine voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a margin of 15.37%.

Results

1884 United States presidential election in Maine[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 72,217 55.34% 6 100.00%
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 52,153 39.97% 0 0.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 3,955 3.03% 0 0.00%
Prohibition John Pierce St. John of Kansas William Daniel of Maryland 2,160 1.65% 0 0.00%
N/A Others Others 6 0.01% 0 0.00%
Total 130,491 100.00% 6 100.00%

References

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.