1793 Pennsylvania gubernatorial election

The Pennsylvania gubernatorial election of 1793 occurred on November 5, 1793. Incumbent Democratic-Republican governor Thomas Mifflin sought re-election to another term, defeating Federalist candidate and U.S. Representative Frederick Muhlenberg. Muhlenberg only won two counties: York and Bedford. However, Mifflin's 2-1 vote margin was down from his 10-1 victory margin in the 1790 gubernatorial election.[1]

Pennsylvania gubernatorial election, 1793

November 5, 1793 (1793-11-05)
 
Candidate Thomas Mifflin Frederick Muhlenberg
Party Democratic-Republican Federalist
Popular vote 20,479 10,803
Percentage 65.4% 34.5%

County Results


McKean:      50-60%      60-70%      70-80%      80-90%      90-100%
Ross:      50-60%

     60-70%

Governor before election

Thomas Mifflin
Democratic-Republican

Elected Governor

Thomas Mifflin
Democratic-Republican

Results

Pennsylvania gubernatorial election, 1793[2][3]
Party Candidate Votes %
Democratic-Republican Thomas Mifflin 20,479 65.43
Federalist Frederick Muhlenberg 10,803 34.51
Independent Alexander McDowell 8 0.03
N/A Others 11 0.04
Total votes 31,301 100.00

References

  1. Tinkcom, Harry Marlin. 1950. The Republicans and Federalists in Pennsylvania: 1790-1801. Harrisburg: Pennsylvania Historical and Museum Commission, p. 138
  2. "PA Governor General Election". OurCampaigns. Retrieved 3 July 2012.
  3. "Pennsylvania Gubernatorial Election Returns 1793". House of Representatives of the Commonwealth of Pennsylvania. Retrieved 3 July 2012.
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