2018 Hong Kong Tennis Open – Doubles

Doubles
2018 Hong Kong Tennis Open
Champions Australia Samantha Stosur
China Zhang Shuai
Runners-up Japan Shuko Aoyama
Belarus Lidziya Marozava
Final score 6–4, 6–4

Chan Hao-ching and Latisha Chan were the defending champions, but Latisha could not participate due to a medical condition. Hao-ching played alongside Yang Zhaoxuan, but they lost in the first round to Nadiia Kichenok and Anastasia Rodionova.

Samantha Stosur and Zhang Shuai won the title, defeating Shuko Aoyama and Lidziya Marozava in the final, 6–4, 6–4.

Seeds

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
1 Chinese Taipei H-c Chan
China Z Yang
4 3
  Ukraine N Kichenok
Australia An Rodionova
6 6 Ukraine N Kichenok
Australia An Rodionova
77 6
  Japan N Hibino
Georgia (country) O Kalashnikova
3 6 [7] Slovenia D Jakupović
Czech Republic R Voráčová
63 1
  Slovenia D Jakupović
Czech Republic R Voráčová
6 2 [10] Ukraine N Kichenok
Australia An Rodionova
6 3 [7]
4 Japan S Aoyama
Belarus L Marozava
4 6 [10] 4 Japan S Aoyama
Belarus L Marozava
4 6 [10]
  Serbia A Krunić
Australia Ar Rodionova
6 2 [8] 4 Japan S Aoyama
Belarus L Marozava
6 3 [10]
WC Hong Kong E Chong
Hong Kong L Zhang
1 2 France A Cornet
China S Zheng
3 6 [7]
  France A Cornet
China S Zheng
6 6 4 Japan S Aoyama
Belarus L Marozava
4 4
  Australia P Hon
Hungary F Stollár
4 4 Australia S Stosur
China S Zhang
6 6
  Australia S Stosur
China S Zhang
6 6 Australia S Stosur
China S Zhang
6 77
WC Hong Kong K-y Ng
Ukraine E Svitolina
1 3 3 Japan M Kato
Japan M Ninomiya
4 65
3 Japan M Kato
Japan M Ninomiya
6 6 Australia S Stosur
China S Zhang
6 6
  Chile A Guarachi
Mexico G Olmos
6 6 Chile A Guarachi
Mexico G Olmos
4 1
  Netherlands L Kerkhove
Netherlands B Schoofs
2 4 Chile A Guarachi
Mexico G Olmos
3 6 [10]
  United States J Brady
Romania M Niculescu
2 3 2 Poland A Rosolska
United States A Spears
6 3 [6]
2 Poland A Rosolska
United States A Spears
6 6

References

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