2018 Silicon Valley Classic – Doubles
Doubles | |
---|---|
2018 Silicon Valley Classic | |
Champions |
|
Runners-up |
|
Final score | 6–4, 6–1 |
Abigail Spears and CoCo Vandeweghe were the defending champions, but chose not to participate this year.
Latisha Chan and Květa Peschke won the title, defeating Lyudmyla and Nadiia Kichenok in the final, 6–4, 6–1.
Seeds
Latisha Chan / Květa Peschke (Champions) Mihaela Buzărnescu / Heather Watson (Semifinals) Lyudmyla Kichenok / Nadiia Kichenok (Final) Miyu Kato / Makoto Ninomiya (Semifinals)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | w/o | ||||||||||||||||||||||||||
4 | 1 | ||||||||||||||||||||||||||
6 | 6 | 1 | 6 | 6 | |||||||||||||||||||||||
4 | 1 | 7 | [10] | 4 | 1 | 4 | |||||||||||||||||||||
6 | 5 | [4] | 4 | 6 | 6 | ||||||||||||||||||||||
4 | 4 | 4 | 2 | ||||||||||||||||||||||||
6 | 6 | 1 | 6 | 6 | |||||||||||||||||||||||
3 | 3 | 3 | 4 | 1 | |||||||||||||||||||||||
6 | 6 | 6 | 2 | [6] | |||||||||||||||||||||||
6 | 3 | [7] | 3 | 1 | 6 | [10] | |||||||||||||||||||||
3 | 4 | 6 | [10] | 3 | 6 | 3 | [10] | ||||||||||||||||||||
3 | 2 | 2 | 4 | 6 | [8] | ||||||||||||||||||||||
6 | 6 | 5 | 2 | ||||||||||||||||||||||||
WC | 3 | 3 | 2 | 7 | 6 | ||||||||||||||||||||||
2 | 6 | 6 |
References
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