Partition (number theory)

The partition 6 + 4 + 3 + 1 of the positive number 14 can be represented by the following diagram:

The 14 circles are lined up in 4 rows, each having the size of a part of the partition. The diagrams for the 5 partitions of the number 4 are listed below:

4	=	3 + 1	=	2 + 2	=	2 + 1 + 1	=	1 + 1 + 1 + 1

An alternative visual representation of an integer partition is its Young diagram (often also called a Ferrers diagram). Rather than representing a partition with dots, as in the Ferrers diagram, the Young diagram uses boxes or squares. Thus, the Young diagram for the partition 5 + 4 + 1 is

while the Ferrers diagram for the same partition is

While this seemingly trivial variation doesn't appear worthy of separate mention, Young diagrams turn out to be extremely useful in the study of symmetric functions and group representation theory: filling the boxes of Young diagrams with numbers (or sometimes more complicated objects) obeying various rules leads to a family of objects called Young tableaux, and these tableaux have combinatorial and representation-theoretic significance.[1] As a type of shape made by adjacent squares joined together, Young diagrams are a special kind of polyomino.[2]

If we flip the diagram of the partition 6 + 4 + 3 + 1 along its main diagonal, we obtain another partition of 14:

	↔
6 + 4 + 3 + 1	=	4 + 3 + 3 + 2 + 1 + 1

By turning the rows into columns, we obtain the partition 4 + 3 + 3 + 2 + 1 + 1 of the number 14. Such partitions are said to be conjugate of one another.[6] In the case of the number 4, partitions 4 and 1 + 1 + 1 + 1 are conjugate pairs, and partitions 3 + 1 and 2 + 1 + 1 are conjugate of each other. Of particular interest is the partition 2 + 2, which has itself as conjugate. Such a partition is said to be self-conjugate.[7]

Claim: The number of self-conjugate partitions is the same as the number of partitions with distinct odd parts.

Proof (outline): The crucial observation is that every odd part can be "folded" in the middle to form a self-conjugate diagram:

↔

One can then obtain a bijection between the set of partitions with distinct odd parts and the set of self-conjugate partitions, as illustrated by the following example:

	↔
9 + 7 + 3	=	5 + 5 + 4 + 3 + 2
Dist. odd		self-conjugate

Among the 22 partitions of the number 8, there are 6 that contain only odd parts:

• 7 + 1
• 5 + 3
• 5 + 1 + 1 + 1
• 3 + 3 + 1 + 1
• 3 + 1 + 1 + 1 + 1 + 1
• 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1

Alternatively, we could count partitions in which no number occurs more than once. Such a partition is called a partition with distinct parts. If we count the partitions of 8 with distinct parts, we also obtain 6:

• 8
• 7 + 1
• 6 + 2
• 5 + 3
• 5 + 2 + 1
• 4 + 3 + 1

This is a general property. For each positive number, the number of partitions with odd parts equals the number of partitions with distinct parts, denoted by q(n).[8][9] This result was proved by Leonhard Euler in 1748[10] and later was generalized as Glaisher's theorem.

For every type of restricted partition there is a corresponding function for the number of partitions satisfying the given restriction. An important example is q(n). The first few values of q(n) are (starting with q(0)=1):

1, 1, 1, 2, 2, 3, 4, 5, 6, 8, 10, ... (sequence A000009 in the OEIS).

The generating function for q(n) (partitions into distinct parts) is given by[11]

${\displaystyle \sum _{n=0}^{\infty }q(n)x^{n}=\prod _{k=1}^{\infty }(1+x^{k})=\prod _{k=1}^{\infty }{\frac {1}{1-x^{2k-1}}}.}$

The pentagonal number theorem gives a recurrence for q:[12]

q(k) = a_k + q(k − 1) + q(k − 2) − q(k − 5) − q(k − 7) + q(k − 12) + q(k − 15) − q(k − 22) − ...

where a_k is (−1)^m if k = 3m² − m for some integer m and is 0 otherwise.

By taking conjugates, the number p_k(n) of partitions of n into exactly k parts is equal to the number of partitions of n in which the largest part has size k. The function p_k(n) satisfies the recurrence

p_k(n) = p_k(n − k) + p_k−1(n − 1)

with initial values p₀(0) = 1 and p_k(n) = 0 if n ≤ 0 or k ≤ 0 and n and k are not both zero.[13]

One recovers the function p(n) by

${\displaystyle p(n)=\sum _{k=1}^{n}p_{k}(n).}$

One possible generating function for such partitions, taking k fixed and n variable, is

${\displaystyle \sum _{n\geq 0}p_{k}(n)x^{n}=x^{k}\cdot \prod _{i=1}^{k}{\frac {1}{1-x^{i}}}.}$

More generally, if T is a set of positive integers then the number of partitions of n, all of whose parts belong to T, has generating function

${\displaystyle \prod _{t\in T}(1-x^{t})^{-1}.}$

This can be used to solve change-making problems (where the set T specifies the available coins). As two particular cases, one has that the number of partitions of n in which all parts are 1 or 2 (or, equivalently, the number of partitions of n into 1 or 2 parts) is

${\displaystyle \left\lfloor {\frac {n}{2}}+1\right\rfloor ,}$

and the number of partitions of n in which all parts are 1, 2 or 3 (or, equivalently, the number of partitions of n into at most three parts) is the nearest integer to (n + 3)² / 12.[14]

The asymptotic growth rate for p(n) is given by

${\displaystyle \log p(n)\sim C{\sqrt {n}}{\text{ as }}n\rightarrow \infty }$

where ${\displaystyle C=\pi {\sqrt {\frac {2}{3}}}.}$[15]

If A is a set of natural numbers, we let p_A(n) denote the number of partitions of n into elements of A. If A possesses positive natural density α then

${\displaystyle \log p_{A}(n)\sim C{\sqrt {\alpha n}}}$

and conversely if this asymptotic property holds for p_A(n) then A has natural density α.[16] This result was stated, with a sketch of proof, by Erdős in 1942.[17][18]

If A is a finite set, this analysis does not apply (the density of a finite set is zero). If A has k elements whose greatest common divisor is 1, then[19]

${\displaystyle p_{A}(n)=\left(\prod _{a\in A}a^{-1}\right)\cdot {\frac {n^{k-1}}{(k-1)!}}+O(n^{k-2}).}$

One may also simultaneously limit the number and size of the parts. Let p(N, M; n) denote the number of partitions of n with at most M parts, each of size at most N. Equivalently, these are the partitions whose Young diagram fits inside an M × N rectangle. There is a recurrence relation

${\displaystyle p(N,M;n)=p(N,M-1;n)+p(N-1,M;n-M)}$

obtained by observing that ${\displaystyle p(N,M;n)-p(N,M-1;n)}$ counts the partitions of n into exactly M parts of size at most N, and subtracting 1 from each part of such a partition yields a partition of n − M into at most M parts.[20]

The Gaussian binomial coefficient is defined as:

${\displaystyle {k+\ell \choose \ell }_{q}={k+\ell \choose k}_{q}={\frac {\prod _{j=1}^{k+\ell }(1-q^{j})}{\prod _{j=1}^{k}(1-q^{j})\prod _{j=1}^{\ell }(1-q^{j})}}.}$

The Gaussian binomial coefficient is related to the generating function of p(N, M; n) by the equality

${\displaystyle \sum _{n=0}^{MN}p(N,M;n)q^{n}={M+N \choose M}_{q}.}$