True anomaly

For elliptic orbits, the true anomaly ν can be calculated from orbital state vectors as:

${\displaystyle \nu =\arccos {{\mathbf {e} \cdot \mathbf {r} } \over {\mathbf {\left|e\right|} \mathbf {\left|r\right|} }}}$

(if r ⋅ v < 0 then replace ν by 2π − ν)

where:

• v is the orbital velocity vector of the orbiting body,
• e is the eccentricity vector,
• r is the orbital position vector (segment FP in the figure) of the orbiting body.

For circular orbits the true anomaly is undefined, because circular orbits do not have a uniquely determined periapsis. Instead the argument of latitude u is used:

${\displaystyle u=\arccos {{\mathbf {n} \cdot \mathbf {r} } \over {\mathbf {\left|n\right|} \mathbf {\left|r\right|} }}}$

(if r_z < 0 then replace u by 2π − u)

where:

• n is a vector pointing towards the ascending node (i.e. the z-component of n is zero).
• r_z is the z-component of the orbital position vector r

For circular orbits with zero inclination the argument of latitude is also undefined, because there is no uniquely determined line of nodes. One uses the true longitude instead:

${\displaystyle l=\arccos {r_{x} \over {\mathbf {\left|r\right|} }}}$

(if v_x > 0 then replace l by 2π − l)

where:

• r_x is the x-component of the orbital position vector r
• v_x is the x-component of the orbital velocity vector v.

The relation between the true anomaly ν and the eccentric anomaly E is:

${\displaystyle \cos {\nu }={{\cos {E}-e} \over {1-e\cos {E}}}}$

or using the sine[1] and tangent:

${\displaystyle {\begin{aligned}\sin {\nu }&={{{\sqrt {1-e^{2}\,}}\sin {E}} \over {1-e\cos {E}}}\\[4pt]\tan {\nu }={{\sin {\nu }} \over {\cos {\nu }}}&={{{\sqrt {1-e^{2}\,}}\sin {E}} \over {\cos {E}-e}}\end{aligned}}}$

or equivalently:

${\displaystyle \tan {\nu \over 2}={\sqrt {{1+e\,} \over {1-e\,}}}\tan {E \over 2}}$

so

${\displaystyle \nu =2\,\operatorname {arctan} \left(\,{\sqrt {{1+e\,} \over {1-e\,}}}\tan {E \over 2}\,\right)}$

An equivalent form avoids the singularity as e → 1, however it does not produce the correct value for ${\displaystyle \nu \,}$:

${\displaystyle \nu =2\,\operatorname {arg} \left({\sqrt {1-e\,}}\,\cos {\frac {E}{2}},\;{\sqrt {1+e\,}}\sin {\frac {E}{2}}\right)}$

or, with the same problem as e → 1 ,

${\displaystyle \nu =\operatorname {arg} \left(\cos {E}-e,\;{\sqrt {1-e^{2}\,}}\sin {E}\right)}$.

In both of the above, the function arg(x, y) is the polar argument of the vector (x y), available in many programming languages as the library function named atan2(y,x) (note the reversed order of x and y).

The true anomaly can be calculated directly from the mean anomaly via a Fourier expansion:[2]

${\displaystyle \nu =M+\left(2e-{\frac {1}{4}}e^{3}\right)\sin {M}+{\frac {5}{4}}e^{2}\sin {2M}+{\frac {13}{12}}e^{3}\sin {3M}+\operatorname {O} \left(e^{4}\right)}$

where the "big-O" notation means that the omitted terms are all of order e⁴.

The expression ${\displaystyle \nu -M}$ is known as the equation of the center.

The radius (distance from the focus of attraction and the orbiting body) is related to the true anomaly by the formula

${\displaystyle r=a\,{1-e^{2} \over 1+e\cos \nu }\,\!}$

where a is the orbit's semi-major axis.