Adrian, Wisconsin

According to the United States Census Bureau, the town has a total area of 35.3 square miles (91.3 km²), of which, 35.3 square miles (91.3 km²) of it is land and 0.03% is water.

At the 2000 census there were 682 people in 231 households, including 188 families, in the town. The population density was 19.3 people per square mile (7.5/km²). There were 248 housing units at an average density of 7.0 per square mile (2.7/km²). The racial makeup of the town was 99.41% White, 0.15% African American, 0.15% Native American, and 0.29% from two or more races. Hispanic or Latino of any race were 0.15%.[2]

Of the 231 households 46.3% had children under the age of 18 living with them, 71.4% were married couples living together, 5.2% had a female householder with no husband present, and 18.6% were non-families. 15.6% of households were one person and 5.6% were one person aged 65 or older. The average household size was 2.95 and the average family size was 3.32.

The age distribution was 31.7% under the age of 18, 7.0% from 18 to 24, 31.4% from 25 to 44, 22.4% from 45 to 64, and 7.5% 65 or older. The median age was 36 years. For every 100 females, there were 111.8 males. For every 100 females age 18 and over, there were 110.9 males.

The median household income was $45,875 and the median family income was $51,786. Males had a median income of $31,583 versus $25,673 for females. The per capita income for the town was $19,791. About 1.0% of families and 2.1% of the population were below the poverty line, including none of those under age 18 and 13.4% of those age 65 or over.