1996 Fed Cup Americas Zone

• Venue: Club Palestino, Santiago, Chile (outdoor clay)
• Date: 22–28 April

The eight teams were divided into two pools of four teams. The top two teams of each pool play-off in a two-round knockout stage to decide which nation progresses to World Group II play-offs. Nations finishing in the bottom place in each pool were relegated to Americas Zone Group II for 1997.

Pools

	Pool A	CHI	COL	MEX	PAR
1	Chile (3–0)		2–1	2–1	2–1
2	Colombia (2–1)	1–2		2–1	2–1
3	Mexico (1–2)	1–2	1–2		2–1
4	Paraguay (0–3)	1–2	1–2	1–2

	Pool B	VEN	BRA	PUR	URU
1	Venezuela (3–0)		3–0	3–0	3–0
2	Brazil (2–1)	0–3		3–0	3–0
3	Puerto Rico (1–2)	0–3	0–3		2–1
4	Uruguay (0–3)	0–3	0–3	1–2

Knockout Stage

Main article: 1996 Fed Cup Americas Zone Group I – Knockout Stage

	Semifinals 27 April					Final 28 April
		Chile	2
		Brazil	1
							Chile	2
							Colombia	1
		Colombia	2
		Venezuela	1

•  Chile advanced to World Group II Play-offs.[1]
•  Paraguay and  Uruguay relegated to Group II in 1997.[2][3]

• Venue: Santo Domingo, Dominican Republic (outdoor clay)
• Date: 6–12 May

The thirteen teams were divided into two pools of six and seven. The top team from each pool then moved would advance to Group I for 1997.

Pools

	Pool A	ECU	BOL	ESA	GUA	BAH	BAR
1	Ecuador (5–0)		3–0	3–0	3–0	3–0	3–0
2	Bolivia (4–1)	0–3		3–0	3–0	3–0	3–0
3	El Salvador (3–2)	0–3	0–3		3–0	3–0	3–0
4	Guatemala (2–3)	0–3	0–3	0–3		2–1	3–0
5	Bahamas (1–4)	0–3	0–3	0–3	1–2		2–1
6	Barbados (0–5)	0–3	0–3	0–3	0–3	1–2

	Pool B	PER	CUB	DOM	CRC	TRI	JAM	BER
1	Peru (5–1)		1–2	3–0	3–0	2–1	3–0	3–0
2	Cuba (5–1)	2–1		1–2	3–0	3–0	3–0	3–0
3	Dominican Republic (5–1)	0–3	2–1		2–1	3–0	2–1	3–0
4	Costa Rica (3–3)	0–3	0–3	1–2		3–0	2–1	2–1
5	Trinidad and Tobago (2–4)	1–2	0–3	0–3	0–3		2–1	3–0
6	Jamaica (1–5)	0–3	0–3	1–2	1–2	1–2		3–0
7	Bermuda (0–6)	0–3	0–3	0–3	1–2	0–3	0–3

•  Ecuador and  Peru advanced to Group I in 1997.[4][5]

• Fed Cup structure

• Fed Cup website