1967 CONCACAF Championship qualification

For the 1967 CONCACAF Championship, a total of 10 teams entered the competition.  Honduras, as the hosts, and  Mexico, as the defending champions, qualified automatically, leaving 4 spots open for competition. The 8 teams were divided into 2 groups in which the top 2 in each group advanced to the final tournament.

Group 1

Played in Kingston, Jamaica.

The group was also referred to as the Red Stripe Trophy within Jamaica. The group was sponsored by Desnoes & Geddes, the brewery of Red Stripe beer.[1]

Pos Team Pld W D L GF GA GD Pts
1  Haiti 4 3 1 0 7 3 +4 7
2  Trinidad and Tobago 4 2 1 1 7 7 0 5
3  Jamaica 4 1 2 1 4 4 0 4
4  Cuba 4 0 2 2 5 7 −2 2
5  Netherlands Antilles 4 0 2 2 4 6 −2 2
Source:
Jamaica 1–1 Netherlands Antilles
Cuba 1–1 Haiti
Trinidad and Tobago 2–1 Netherlands Antilles
Small
Archibald 		Perez  (pen)
Jamaica 2–1 Cuba
Haiti 4–2 Trinidad and Tobago
Netherlands Antilles 2–2 Cuba
Dirks
Perez 		Hernandez
Mico
Jamaica 1–1 Trinidad and Tobago
Haiti 1–0 Netherlands Antilles
Trinidad and Tobago 2–1 Cuba
Jamaica 0–1 Haiti

Haiti and Trinidad and Tobago qualified for the final tournament.

Group 2

Played in Ciudad de Guatemala, Guatemala.

Pos Team Pld W D L GF GA GD Pts
1  Guatemala 2 2 0 0 6 2 +4 4
2  Nicaragua 2 1 0 1 4 4 0 2
3  Panama 2 0 0 2 2 6 −4 0
Source:
Guatemala 3–1 Panama
Guatemala 3–1 Nicaragua
Panama 1–3 Nicaragua

Guatemala and Nicaragua qualified for the final tournament.

References
  1. "Haitian goalkeeper suspended". Kingston Gleaner. 23 January 1967. p. 28.
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