1956 UEFA European Under-18 Championship

The UEFA European Under-18 Championship 1956 Final Tournament was held in Hungary. During this edition, only group matches were played and no winner was declared. This was done to prevent an excess of competition. Hungary, Italy, Romania and Czechoslovakia were the four group winners.

1956 UEFA European Under-18 Championship
Tournament details
Host countryHungary
Dates28 March - 2 April
Teams16

Teams

The following teams entered the tournament:

Group A

Teams Pld W D L GF GA GD Pts
 Hungary 321063+35
 West Germany 31112203
 Bulgaria 310234–12
 England 310257–22


28 March Hungary  0–0  West Germany
Bulgaria  2–1  England
30 March West Germany  1–0  Bulgaria
Hungary  4–2  England
1 April Hungary  2–1  Bulgaria
England  2–1  West Germany

Group B

Teams Pld W D L GF GA GD Pts
 Italy 320152+34
 France 320143+14
 Saar 311135–23
 Belgium 301257–21


28 March Saar  1–0  France
Italy  2–1  Belgium
30 March France  3–2  Belgium
Italy  3–0  Saar
1 April Saar  2–2  Belgium
France  1–0  Italy

Group C

Teams Pld W D L GF GA GD Pts
 Romania 321062+45
 Poland 31114403
 Yugoslavia 302123–12
 Austria 310247–32


29 March Romania  1–1  Yugoslavia
Poland  3–2  Austria
31 March Austria  1–0  Yugoslavia
Romania  1–0  Poland
2 April Romania  4–1  Austria
Poland  1–1  Yugoslavia

Group D

Teams Pld W D L GF GA GD Pts
 Czechoslovakia 321041+35
 Turkey 311142+23
 East Germany 30303303
 Greece 301216–51


29 March Czechoslovakia  2–0  Greece
East Germany  1–1  Turkey
31 March Czechoslovakia  1–1  East Germany
Turkey  3–0  Greece
2 April Czechoslovakia  1–0  Turkey
East Germany  1–1  Greece
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