1948 U.S. National Championships – Women's Singles

Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the Women's Singles tennis title at the 1948 U.S. National Championships.[1][2]

Women's Singles
1948 U.S. National Championships
Champion Margaret Osborne duPont[1]
Runner-up Louise Brough
Final score4–6, 6–4, 15–13

Seeds

The seven seeded U.S. players are listed below. Margaret Osborne duPont is the champion; others show in brackets the round in which they were eliminated.[3]

  1. Louise Brough (Finalist)
  2. Doris Hart (Quarterfinalist)
  3. Margaret Osborne duPont (Champion)
  4. Pat Canning Todd (Semifinalist)
  5. Shirley Fry (Third round)
  6. Beverly Baker (Quarterfinalist)
  7. Gussy Moran (Semifinalist)

Draw

Key
  • Q = Qualifier
  • WC = Wild Card
  • LL = Lucky Loser
  • r. = retired

Final Eight
Quarterfinals Semifinals Finals
               
7 Gussy Moran 6 6
2 Doris Hart 4 4
7 Gussy Moran 8 4
3 Margaret Osborne duPont 10 6
3 Margaret Osborne duPont 1 6 6
Beverly Baker 6 2 0
3 Margaret Osborne duPont 4 6 15
1 Louise Brough 6 4 13
1 Louise Brough 6 6
Virginia Kovacs 3 2
1 Louise Brough 6 6
4 Pat Canning Todd 3 3
4 Pat Canning Todd 6 6
Madge Vosters 3 1

References
  1. Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0942257700.
  2. "Exciting Game for Tennis Title". Cairns Post (Qld. : 1909 - 1954). Qld.: National Library of Australia. 21 September 1948. p. 1.
  3. G.P. Hughes, ed. (1949). Dunlop Lawn Tennis Annual and Almanack 1949. London: Ed. J. Burrow & Co. Ltd. pp. 159–164.
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