1936 United States presidential election in Rhode Island
The 1936 United States presidential election in Rhode Island was held on November 3, 1936. The state voters chose 4 electors to the Electoral College, who voted for president and vice president.
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Elections in Rhode Island | ||||||
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Rhode Island voted for Democratic Party candidate and incumbent President Franklin D. Roosevelt, who won the state by a margin of 12.92%.
Results
1936 United States presidential election in Rhode Island[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Franklin Delano Roosevelt of New York | John Nance Garner of Texas | 165,238 | 53.10% | 4 | 100.00% | ||
Republican | Alf Landon of Kansas | Frank Knox of Illinois | 125,031 | 40.18% | 0 | 0.00% | ||
Union | William Lemke of North Dakota | Thomas C. O'Brien of Massachusetts | 19,569 | 6.29% | 0 | 0.00% | ||
Socialist Labor | John W. Aiken of Connecticut | Emil F. Teichert of New York | 929 | 0.30% | 0 | 0.00% | ||
Communist | Earl Russell Browder of Kansas | James W. Ford of New York | 411 | 0.13% | 0 | 0.00% | ||
Total | 311,178 | 100.00% | 4 | 100.00% |
References
- "1936 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved 23 December 2013.
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