San Leandro Hills
| San Leandro Hills | |
|---|---|
  location of San Leandro Hills in California [1] | |
| Highest point | |
| Elevation | 314 m (1,030 ft) |
| Geography | |
| Country | United States |
| State | California |
| Region | California Coast Ranges |
| District | Alameda County |
| Range coordinates | 37°44′49.743″N 122°5′46.869″W / 37.74715083°N 122.09635250°WCoordinates: 37°44′49.743″N 122°5′46.869″W / 37.74715083°N 122.09635250°W |
| Topo map | USGS Hayward |
The San Leandro Hills are a low mountain range of the Southern Inner California Coast Ranges System, located on the eastern side of the San Francisco Bay. Geologically, they are a southern continuation of the Berkeley Hills on the north.
They run along the southeastern city limits of Oakland, extending southeastward above the city of San Leandro and the unincorporated community of Castro Valley.
San Leandro Creek drains the canyon along the eastern slope of the hills.
References
- ↑ "San Leandro Hills". Geographic Names Information System. United States Geological Survey. Retrieved 2009-05-04.
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