Rowland Brotherhood (cricketer)

Rowland Brotherhood
Personal information
Full name Rowland Brotherhood
Born (1841-11-18)18 November 1841
Brinkworth, Wiltshire, England
Batting Left-handed
Bowling Left-arm underarm fast
Domestic team information
YearsTeam
1875 Gloucestershire
Career statistics
Competition First-class
Matches 3
Runs scored 3
Batting average 0.75
100s/50s –/–
Top score 2
Balls bowled 120
Wickets 2
Bowling average 33.50
5 wickets in innings
10 wickets in match
Best bowling 2/49
Catches/stumpings 1/–
Source: Cricinfo, 27 July 2011

Rowland Brotherhood (18 November 1841 – before 1938) was an English cricketer and civil engineer. Brotherhood was a left-handed batsman who bowled left-arm underarm fast. One of 14 children of the engineer Rowland Brotherhood and his wife Priscilla, he was born in Brinkworth, Wiltshire; his date and place of death are unknown.

He made his first-class debut for Gloucestershire against Sussex in 1875. He made 2 further first-class appearances, both in 1875, against Yorkshire and Nottinghamshire.[1] In his 3 matches, he took 2 wickets at an average of 33.50, with best figures of 2/49.[2]

From 1877 to 1879 Brotherhood was assisted by his father in sinking shafts for the Severn Tunnel. He practised as a consulting civil engineer with offices in Victoria Street, Westminster, alongside many other consulting engineers, but in 1892, his office was put into receivership.[3] His death is not recorded, but his younger brother John died in 1938 and the notice of his death in The Times indicates that he was the last surviving son of Rowland Brotherhood, senior.[4]

References

  1. "First-Class Matches played by Rowland Brotherhood". CricketArchive. Retrieved 26 July 2011.
  2. "First-class Bowling For Each Team by Rowland Brotherhood". CricketArchive. Retrieved 27 July 2011.
  3. "The Bankruptcy Acts, Receiving Orders", The Times, London (33668), p. 14, 1892-06-18 |access-date= requires |url= (help)
  4. "Deaths", The Times, London (48141), p. 1, 1938-11-02 |access-date= requires |url= (help)
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