Lewis Island (Antarctica)

Lewis Island
Lewis Island
Location in Antarctica
Geography
Location Antarctica
Coordinates 66°6′S 134°22′E / 66.100°S 134.367°E / -66.100; 134.367Coordinates: 66°6′S 134°22′E / 66.100°S 134.367°E / -66.100; 134.367
Highest elevation 30 m (100 ft)
Administration
Administered under the Antarctic Treaty System
Demographics
Population Uninhabited

Lewis Island is a small rocky island rising to 30 metres (100 ft), marking the east side of the entrance to Davis Bay in Antarctica. It was delineated from air photos taken by U.S. Navy Operation Highjump (1946–47) and named by the Advisory Committee on Antarctic Names for James B. Lewis, Passed Midshipman on the sloop Peacock of the U.S. Exploring Expedition (183842) under Charles Wilkes.[1]

See also

References

  1. "Lewis Island". Geographic Names Information System. United States Geological Survey. Retrieved 2013-06-13.

 This article incorporates public domain material from the United States Geological Survey document "Lewis Island (Antarctica)" (content from the Geographic Names Information System).


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