2018 Brisbane International – Men's Doubles

Men's Doubles
2018 Brisbane International
Champions	Henri Kontinen John Peers
Runners-up	Leonardo Mayer Horacio Zeballos
Final score	3–6, 6–3, [10–2]

Thanasi Kokkinakis and Jordan Thompson were the defending champions, but Kokkinakis chose to compete in the Hopman Cup instead. Thompson played alongside Lleyton Hewitt, but lost in the first round to Grigor Dimitrov and Ryan Harrison.

Henri Kontinen and John Peers won the title, defeating Leonardo Mayer and Horacio Zeballos in the final, 3–6, 6–3, [10–2].

Seeds

Draw

Draw

	First Round							Quarterfinals							Semifinals							Final
	1	H Kontinen J Peers	77	6
		M Raonic D Shapovalov	63	4				1	H Kontinen J Peers	6	6
	PR	I Bozoljac D Džumhur	1	2				PR	M Ebden J Millman	4	3
	PR	M Ebden J Millman	6	6											1	H Kontinen J Peers	w/o
	4	M Daniell D Inglot	6	1	[7]											G Dimitrov R Harrison
		N Kyrgios M Reid	4	6	[10]				N Kyrgios M Reid	62	63
	WC	L Hewitt J Thompson	3	6	[5]				G Dimitrov R Harrison	77	77
		G Dimitrov R Harrison	6	1	[10]																	1	H Kontinen J Peers	3	6	[10]
		W Koolhof A Sitak	6	6																			L Mayer H Zeballos	6	3	[2]
		T Huey F Martin	3	2					W Koolhof A Sitak	78	7
		S Johnson G Müller	77	4	[11]				S Johnson G Müller	66	5
	3	S González J Peralta	62	6	[9]											W Koolhof A Sitak	6	1	[6]
		D Schwartzman M Zverev	2	0												L Mayer H Zeballos	4	6	[10]
		L Mayer H Zeballos	6	6					L Mayer H Zeballos	77	65	[13]
		N Monroe J-P Smith	6	3	[5]			2	M Demoliner M Venus	61	77	[11]
	2	M Demoliner M Venus	4	6	[10]

References

• Main Draw