1998 Boston Cup – Singles

Singles
1998 Boston Cup
Champion	Mariaan de Swardt
Runner-up	Barbara Schett
Final score	3–6, 7–6, 7–5

Mariaan de Swardt won in the final 3–6, 7–6, 7–5 against Barbara Schett.

Seeds

A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated. The top two seeds received a bye to the second round.

Draw

Final

	Final
	7	Barbara Schett	6	6	5
		Mariaan de Swardt	3	7	7

Section 1

	First Round							Second Round							Quarterfinals							Semifinals
								1	A Coetzer	6	6
		R McQuillan	4	2				Q	N Miyagi	3	3
	Q	N Miyagi	6	6											1	A Coetzer	7	4	1
	Q	L Horn	4	1											7	B Schett	6	6	6
		C Cristea	6	6					C Cristea	0	5
	Q	K Brandi	4	0				7	B Schett	6	7
	7	B Schett	6	6																		7	B Schett	6	2	6
	4	S Farina	1	6	7																		C Black	2	6	2
		M J Fernández	6	2	5			4	S Farina	6	4	2
		S Plischke	6	6	1				C Black	4	6	6
		C Black	7	3	6											C Black	1	6	6
		S-T Wang	6	6											5	E Likhovtseva	6	1	2
		S Kleinová	0	0					S-T Wang	4	2
		A Glass	1	2	r			5	E Likhovtseva	6	6
	5	E Likhovtseva	6	4

Section 2

	First Round							Second Round							Quarterfinals							Semifinals
	8	C Morariu	6	6
		M Saeki	1	2				8	C Morariu	3	6	6
	WC	M Shaughnessy	6	6				WC	M Shaughnessy	6	1	2
	Q	N Pratt	2	0											8	C Morariu	6	2
	WC	R Dragomir	6	6											3	L Raymond	7	6
		T Panova	1	1				WC	R Dragomir	3	3
		A Frazier	4	2				3	L Raymond	6	6
	3	L Raymond	6	6																		3	L Raymond	6	4	5
	LL	Y Yoshida	2	4																			M de Swardt	4	6	7
		N Dechy	6	6					N Dechy	1	6
		S Smith	6	3	2				M de Swardt	6	7
		M de Swardt	2	6	6											M de Swardt	6	7
		O Barabanschikova	6	6											2	A Huber	3	6
	WC	E deLone	1	2					O Barabanschikova
								2	A Huber	w/o

External links

• 1998 Boston Cup Draw