1969 New Zealand Open – Singles

Singles
1969 New Zealand Open
Champion Australia Tony Roche[1]
Runner-up Australia Rod Laver
Final score 6–1, 6–4, 4–6, 6–3

Tony Roche defeated Rod Laver 6–1, 6–4, 4–6, 6–3 to win the 1969 New Zealand Open singles event. Barry Phillips-Moore was the champion but did not defend his title.

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1. Australia Tony Roche (Champion)
  2. Australia Rod Laver (Final)

Draw

Key

Finals

Quarterfinals Semifinals Final[1]
                     
1 Australia Tony Roche 6 1 6 6  
  United Kingdom Roger Taylor 2 6 3 2  
1 Australia Tony Roche 6 9 6 6 6
  South Africa Raymond Moore 3 11 4 8 2
  South Africa Raymond Moore 2 12 6 5 9
  United States Pancho Gonzales 6 10 4 7 7
1 Australia Tony Roche 6 6 4 6  
2 Australia Rod Laver 1 4 6 3  
  New Zealand Brian Fairlie 7 4 10 6 6
  Australia John Newcombe 9 6 8 0 3
  New Zealand Brian Fairlie 3 3 6 5  
2 Australia Rod Laver 6 6 3 7  
  Soviet Union Toomas Leius 3 6 6 3 5
2 Australia Rod Laver 6 4 4 6 7

References

  1. 1 2 "1969 Auckland Singles". Association of Tennis Professionals. Retrieved 10 January 2015.
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