Sigma-ring

Let ${\displaystyle {\mathcal {R}}}$ be a nonempty collection of sets. Then ${\displaystyle {\mathcal {R}}}$ is a σ-ring if:

1. ${\displaystyle \bigcup _{n=1}^{\infty }A_{n}\in {\mathcal {R}}}$ if ${\displaystyle A_{n}\in {\mathcal {R}}}$ for all ${\displaystyle n\in \mathbb {N} }$
2. ${\displaystyle A\setminus B\in {\mathcal {R}}}$ if ${\displaystyle A,B\in {\mathcal {R}}}$

From these two properties we immediately see that

${\displaystyle \bigcap _{n=1}^{\infty }A_{n}\in {\mathcal {R}}}$ if ${\displaystyle A_{n}\in {\mathcal {R}}}$ for all ${\displaystyle n\in \mathbb {N} }$

This is simply because ${\displaystyle \cap _{n=1}^{\infty }A_{n}=A_{1}\setminus \cup _{n=2}^{\infty }(A_{1}\setminus A_{n})}$.

If the first property is weakened to closure under finite union (i.e., ${\displaystyle A\cup B\in {\mathcal {R}}}$ whenever ${\displaystyle A,B\in {\mathcal {R}}}$) but not countable union, then ${\displaystyle {\mathcal {R}}}$ is a ring but not a σ-ring.

σ-rings can be used instead of σ-fields (σ-algebras) in the development of measure and integration theory, if one does not wish to require that the universal set be measurable. Every σ-field is also a σ-ring, but a σ-ring need not be a σ-field.

A σ-ring ${\displaystyle {\mathcal {R}}}$ that is a collection of subsets of ${\displaystyle X}$ induces a σ-field for ${\displaystyle X}$. Define ${\displaystyle {\mathcal {A}}=\{A\cup B^{c}|A,B\in {\mathcal {R}}\}}$. Then ${\displaystyle {\mathcal {A}}}$ is a σ-field over the set ${\displaystyle X}$ - to check closure under countable union, recall a ${\displaystyle \sigma }$-ring is closed under countable intersections. In fact ${\displaystyle {\mathcal {A}}}$ is the minimal σ-field containing ${\displaystyle {\mathcal {R}}}$ since it must be contained in every σ-field containing ${\displaystyle {\mathcal {R}}}$.

• Delta ring
• Ring of sets
• Sigma field

• Walter Rudin, 1976. Principles of Mathematical Analysis, 3rd. ed. McGraw-Hill. Final chapter uses σ-rings in development of Lebesgue theory.