Lissajous knot

Because a knot cannot be self-intersecting, the three integers ${\displaystyle n_{x},n_{y},n_{z}}$ must be pairwise relatively prime, and none of the quantities

${\displaystyle n_{x}\phi _{y}-n_{y}\phi _{x},\quad n_{y}\phi _{z}-n_{z}\phi _{y},\quad n_{z}\phi _{x}-n_{x}\phi _{z}}$

may be an integer multiple of pi. Moreover, by making a substitution of the form ${\displaystyle t'=t+c}$, one may assume that any of the three phase shifts ${\displaystyle \phi _{x}}$, ${\displaystyle \phi _{y}}$, ${\displaystyle \phi _{z}}$ is equal to zero.

Here are some examples of Lissajous knots,[3] all of which have ${\displaystyle \phi _{z}=0}$:

• 
  Three-twist knot
  ${\displaystyle (n_{x},n_{y},n_{z})=(3,2,7)}$
  ${\displaystyle (\phi _{x},\phi _{y})=(0.7,0.2)}$
• 
  Stevedore knot
  ${\displaystyle (n_{x},n_{y},n_{z})=(3,2,5)}$
  ${\displaystyle (\phi _{x},\phi _{y})=(1.5,0.2)}$
• 
  Square knot
  ${\displaystyle (n_{x},n_{y},n_{z})=(3,5,7)}$
  ${\displaystyle (\phi _{x},\phi _{y})=(0.7,1.0)}$
• 
  8₂₁ knot
  ${\displaystyle (n_{x},n_{y},n_{z})=(3,4,7)}$
  ${\displaystyle (\phi _{x},\phi _{y})=(0.1,0.7)}$

There are infinitely many different Lissajous knots,[4] and other examples with 10 or fewer crossings include the 7₄ knot, the 8₁₅ knot, the 10₁ knot, the 10₃₅ knot, the 10₅₈ knot, and the composite knot 5₂^* # 5₂,[1] as well as the 9₁₆ knot, 10₇₆ knot, the 10₉₉ knot, the 10₁₂₂ knot, the 10₁₄₄ knot, the granny knot, and the composite knot 5₂ # 5₂.[5] In addition, it is known that every twist knot with Arf invariant zero is a Lissajous knot.[6]

Lissajous knots are highly symmetric, though the type of symmetry depends on whether or not the numbers ${\displaystyle n_{x}}$, ${\displaystyle n_{y}}$, and ${\displaystyle n_{z}}$ are all odd.