Kobon triangle problem

The Kobon triangle problem is an unsolved problem in combinatorial geometry first stated by Kobon Fujimura. The problem asks for the largest number N(k) of nonoverlapping triangles whose sides lie on an arrangement of k lines. Variations of the problem consider the projective plane rather than the Euclidean plane, and require that the triangles not be crossed by any other lines of the arrangement.[1]

Unsolved problem in mathematics: How many non-overlapping triangles can be formed in an arrangement of ${\displaystyle k}$ lines? (more unsolved problems in mathematics)

Kobon triangles generated with 3, 4 and 5 straight line segments.

Saburo Tamura proved that the largest integer not exceeding k(k − 2)/3 provides an upper bound on the maximal number of nonoverlapping triangles realizable by k lines.[2] In 2007, a tighter upper bound was found by Johannes Bader and Gilles Clément, by proving that Tamura's upper bound couldn't be reached for any k congruent to 0 or 2 (mod 6).[3] The maximum number of triangles is therefore at most one less than Tamura's bound in these cases. Perfect solutions (Kobon triangle solutions yielding the maximum number of triangles) are known for k = 3, 4, 5, 6, 7, 8, 9, 13, 15 and 17.[4] For k = 10, 11 and 12, the best solutions known reach a number of triangles one less than the upper bound.

As proved by G. Clément and J. Bader,[3] the solutions for k > 2 are bounded above by

${\displaystyle k(k-2)/3}$, when k=={3, 5} (mod 6);

${\displaystyle (k+1)(k-3)/3}$, when k=={0, 2} (mod 6);

${\displaystyle (k^{2}-2k-2)/3}$, when k=={1, 4} (mod 6).

(The floor function is handled by noting that the expression k(k − 2) is a multiple of 3 in the first case and 2 more than a multiple of 3 in the third case; Clément and Bader only improved the bound on the middle case.)

Given a perfect solution with k₀>3 lines, other Kobon triangle solution numbers can be found for all k_i-values where

${\displaystyle k_{n+1}=2\cdot k_{n}-1,}$

by using the procedure by D. Forge and J. L. Ramirez Alfonsin.[1][5] For example, the solution for k₀ = 5 leads to the maximal number of nonoverlapping triangles for k = 5,9,17,33,65,...