2019 International Challenger Baotou – Doubles

Doubles
	2019 International Challenger Baotou
Champions	Nam Ji-sung; Song Min-kyu
Runners-up	Teymuraz Gabashvili; Sasikumar Mukund
Final score	7–6(7–3), 6–2

Nam Ji-sung and Song Min-kyu won the title after defeating Teymuraz Gabashvili and Sasikumar Mukund 7–6^(7–3), 6–2 in the final.

This was the first edition of the tournament.[1]

Seeds

First Round					Quarterfinals					Semifinals					Final

1	G Oliveira L Saville	6	6
	R Hua Zh Zhang	2	2		1	G Oliveira L Saville	4	7⁷	[10]
WC	Cui Jie Chuh Wang	2	0			Y Bai T-h Yang	6	6⁴	[7]
	Y Bai T-h Yang	6	6							1	G Oliveira L Saville	3	6	[11]
3	JP Fruttero A Kadhe	3	3								T Gabashvili S Mukund	6	3	[13]
	T Gabashvili S Mukund	6	6			T Gabashvili S Mukund	3	6	[10]
	Harry Bourchier R Purcell	3	4			C-h Tseng T-l Wu	6	3	[4]
	C-h Tseng T-l Wu	6	6													T Gabashvili S Mukund	6³	2
	I Nedelko K Takeuchi	7	6												2	J-s Nam M-k Song	7⁷	6
WC	Liu Hanyi Wang Chukang	5	4			I Nedelko K Takeuchi	6⁵	4
	R Ortega Olmedo Evan Song	2	2		4	F Sun D Wu	7⁷	6
4	F Sun D Wu	6	6							4	F Sun D Wu	6⁴	3
	Jacob Grills A Vukic	3	7¹²	[6]						2	J-s Nam M-k Song	7⁷	6
	Luca Castelnuovo Baptiste Crepatte	6	6¹⁰	[10]		L Castelnuovo B Crepatte	6⁵	2
WC	Gao Yixin Wang Huixin	4	5		2	J-s Nam M-k Song	7⁷	6
2	J-s Nam M-k Song	6	7

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