Lake Tașaul
| Tașaul | |
|---|---|
| Location | Northern Dobruja |
| Coordinates | 44°21′00″N 28°36′48″E / 44.35000°N 28.61333°ECoordinates: 44°21′00″N 28°36′48″E / 44.35000°N 28.61333°E |
| Basin countries | Romania |
| Surface area | 22.8 km2 (8.8 sq mi) |
| Max. depth | 5.4 m (18 ft) |
| Surface elevation | 1 m (3.3 ft) |
Tașaul is a lake in Northern Dobruja, Romania.
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